x^2 + (b/a)x + / <4a^2> = -c/a + / <4a^2> factor the right side....get a common denominator on the left
x + (b/2a) =±√/<2a> subtract (b/2a) from both sides
x = (-b±√) / <2a>
Voila!!!....we have the Quadratic Formula..... !!!!
CPhill Mar 22, 2015
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#1

+10
Best Answer
If we do this correctly....we will arrive at a familiar formula....let"s see...
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ax^2+bx+c=0 subtract c from both sides
ax^2 + bx = -c divide through by a
x^2 +(b/a)x = -c/a complete the square on x
x^2 + (b/a)x + / <4a^2> = -c/a + / <4a^2> factor the right side....get a common denominator on the left
x + (b/2a) =±√/<2a> subtract (b/2a) from both sides
x = (-b±√) / <2a>
Voila!!!....we have the Quadratic Formula..... !!!!
CPhill Mar 22, 2015
#2

0
Thanks Chris :)
Melody Mar 22, 2015
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