Since we know that x3 + y3 + z3 – 3xyz = (x + y + z)( x2 + y2 + z2 – xy – yz - zx)
Using (1) and (2) & x + y + z = 9
⇒ x3 + y3 + z3 – 3xyz = 81 × 9
∴ x3 + y3 + z3 – 3xyz = 729
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Q1. The difference of two numbers is 5 và the difference of their squares is 105. Find the average of these numbers.
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Q1. There were 120 students who went for summer camp. đôi mươi students joind them after some time, Due to lớn which the cost of consumption increased by Rs. 80 per day & the average cost of each students decrease by Rs. 5. Find the initial consumption of each student.
Q2. The difference of two numbers is 5 và the difference of their squares is 105. Find the average of these numbers.
Q3. The value of(frac3.57 imes 3.57 imes 3.57 - 1.23 imes 1.23 imes 1.233.57 imes 3.57 + 3.57 imes 1.23 + 1.23 imes 1.23)+ 2.56 will be:
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Q1. If the incomes of Ram & Shyam are in the ratio of 3 ∶ 4 & their expenditures in the ratio of 4 ∶ 5,find the ratio of their savings, given that Shyam saves a third of his income.
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