\$\$frac1A=frac11 +frac11=frac1+11*1=frac21\$\$Hence \$\$A=1/2\$\$

Case 5\$\$frac1A=frac15 +frac15=frac5+55*5=frac1025\$\$Hence \$\$A=25/10=2.5\$\$

I can see in both of these cases \$A\$ is still \$1\$

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asked Nov 20, 2016 at 2:17

K-FeldsparK-Feldspar
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Since everything is strictly positive, it"s simply the fact that \$\$frac1A=frac1B+frac1C>frac1B\$\$ và \$\$frac1A>frac1Bimplies B>A\$\$ Same for \$C\$. Since \$A\$ is smaller than boh, it is smaller than the minimum.

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I don"t really understand why in you decided to lớn consider only three numbers.

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answered Nov 20, 2016 at 2:21
user228113user228113
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blackpen what trick? \$endgroup\$
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Nov 20, năm 2016 at 2:28
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As you said, \$frac1A=fracC+BC*B\$which means \$A=fracB*CB+C\$Now clearly \$B > fracB*CB+C\$ because \$fracB*CB+C = B*fracCB+C\$ và \$fracCB+C Similarly, \$C > fracB*CB+C\$ because \$fracB*CB+C = C*fracBB+C\$ and \$fracBB+C Thus \$B > fracB*CB+C = A\$ & \$C > fracB*CB+C = A\$

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answered Nov 20, 2016 at 2:30

gfppoygfppoy
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